Base | Representation |
---|---|
bin | 1010000111110110101001… |
… | …0010001101011011001011 |
3 | 1110102000120212022000021200 |
4 | 2201331222102031123023 |
5 | 2424323312104004121 |
6 | 35401023225235243 |
7 | 2226055565061534 |
oct | 241755222153313 |
9 | 43360525260250 |
10 | 11130043422411 |
11 | 3601252396a31 |
12 | 12b90b1032b23 |
13 | 6297352c0104 |
14 | 2a69a870568b |
15 | 1447b8248a26 |
hex | a1f6a48d6cb |
11130043422411 has 24 divisors (see below), whose sum is σ = 16081659509760. Its totient is φ = 7417753932336.
The previous prime is 11130043422403. The next prime is 11130043422413. The reversal of 11130043422411 is 11422434003111.
It is a happy number.
11130043422411 is a `hidden beast` number, since 1 + 1 + 1 + 3 + 0 + 0 + 434 + 224 + 1 + 1 = 666.
It is not a de Polignac number, because 11130043422411 - 23 = 11130043422403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11130043422413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 598798660 + ... + 598817246.
It is an arithmetic number, because the mean of its divisors is an integer number (670069146240).
Almost surely, 211130043422411 is an apocalyptic number.
11130043422411 is a deficient number, since it is larger than the sum of its proper divisors (4951616087349).
11130043422411 is a wasteful number, since it uses less digits than its factorization.
11130043422411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35415 (or 35412 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 11130043422411 its reverse (11422434003111), we get a palindrome (22552477425522).
The spelling of 11130043422411 in words is "eleven trillion, one hundred thirty billion, forty-three million, four hundred twenty-two thousand, four hundred eleven".
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