1113012002017 has 2 divisors, whose sum is σ = 1113012002018. Its totient is φ = 1113012002016.

The previous prime is 1113012001993. The next prime is 1113012002027. The reversal of 1113012002017 is 7102002103111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 703852203681 + 409159798336 = 838959^2 + 639656^2 .

It is an emirp because it is prime and its reverse (7102002103111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113012002017 - 2¹¹ = 1113011999969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113012001985 and 1113012002003.

It is not a weakly prime, because it can be changed into another prime (1113012002027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556506001008 + 556506001009.

It is an arithmetic number, because the mean of its divisors is an integer number (556506001009).

Almost surely, 2^{1113012002017} is an apocalyptic number.

It is an amenable number.

1113012002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113012002017 is an equidigital number, since it uses as much as digits as its factorization.

1113012002017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 1113012002017 its reverse (7102002103111), we get a palindrome (8215014105128).

The spelling of 1113012002017 in words is "one trillion, one hundred thirteen billion, twelve million, two thousand, seventeen".