Base | Representation |
---|---|
bin | 10000001100100100110… |
… | …000011100111111011111 |
3 | 10221101212210201101102100 |
4 | 100030210300130333133 |
5 | 121213422340223403 |
6 | 2211151115500143 |
7 | 143261335124343 |
oct | 20144460347737 |
9 | 3841783641370 |
10 | 1113013211103 |
11 | 39a031a3a112 |
12 | 15b861a57653 |
13 | 80c58b242a1 |
14 | 3bc278b1623 |
15 | 1de431622a3 |
hex | 10324c1cfdf |
1113013211103 has 48 divisors (see below), whose sum is σ = 1708731180000. Its totient is φ = 695709665280.
The previous prime is 1113013211099. The next prime is 1113013211117. The reversal of 1113013211103 is 3011123103111.
It is not a de Polignac number, because 1113013211103 - 22 = 1113013211099 is a prime.
It is a super-2 number, since 2×11130132111032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113013211153) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 43428633 + ... + 43454253.
It is an arithmetic number, because the mean of its divisors is an integer number (35598566250).
Almost surely, 21113013211103 is an apocalyptic number.
1113013211103 is a deficient number, since it is larger than the sum of its proper divisors (595717968897).
1113013211103 is a wasteful number, since it uses less digits than its factorization.
1113013211103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26712 (or 26709 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 1113013211103 its reverse (3011123103111), we get a palindrome (4124136314214).
The spelling of 1113013211103 in words is "one trillion, one hundred thirteen billion, thirteen million, two hundred eleven thousand, one hundred three".
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