111303000223 has 4 divisors (see below), whose sum is σ = 112711899040. Its totient is φ = 109894101408.

The previous prime is 111303000197. The next prime is 111303000247. The reversal of 111303000223 is 322000303111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 322000303111 = 131 ⋅2458017581.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111303000223 is a prime.

It is a super-2 number, since 2×111303000223² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111303000197 and 111303000206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111303000323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 704449290 + ... + 704449447.

It is an arithmetic number, because the mean of its divisors is an integer number (28177974760).

Almost surely, 2^111303000223 is an apocalyptic number.

111303000223 is a deficient number, since it is larger than the sum of its proper divisors (1408898817).

111303000223 is an equidigital number, since it uses as much as digits as its factorization.

111303000223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1408898816.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 111303000223 its reverse (322000303111), we get a palindrome (433303303334).

The spelling of 111303000223 in words is "one hundred eleven billion, three hundred three million, two hundred twenty-three", and thus it is an aban number.