Base | Representation |
---|---|
bin | 10100101110110110… |
… | …00111001000010011 |
3 | 1001201200210222012011 |
4 | 22113123013020103 |
5 | 140243340320144 |
6 | 5040243043351 |
7 | 542551564363 |
oct | 122733071023 |
9 | 31650728164 |
10 | 11130401299 |
11 | 47a1904266 |
12 | 21a7670557 |
13 | 1084c53994 |
14 | 7783369a3 |
15 | 45224ba34 |
hex | 2976c7213 |
11130401299 has 2 divisors, whose sum is σ = 11130401300. Its totient is φ = 11130401298.
The previous prime is 11130401291. The next prime is 11130401329. The reversal of 11130401299 is 99210403111.
11130401299 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11130401299 - 23 = 11130401291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11130401299.
It is not a weakly prime, because it can be changed into another prime (11130401291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565200649 + 5565200650.
It is an arithmetic number, because the mean of its divisors is an integer number (5565200650).
Almost surely, 211130401299 is an apocalyptic number.
11130401299 is a deficient number, since it is larger than the sum of its proper divisors (1).
11130401299 is an equidigital number, since it uses as much as digits as its factorization.
11130401299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 11130401299 in words is "eleven billion, one hundred thirty million, four hundred one thousand, two hundred ninety-nine".
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