1113043303301 has 4 divisors (see below), whose sum is σ = 1113046305504. Its totient is φ = 1113040301100.

The previous prime is 1113043303283. The next prime is 1113043303319. The reversal of 1113043303301 is 1033033403111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1113043303283) and next prime (1113043303319).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113043303301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113043300301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851195 + ... + 1717736.

It is an arithmetic number, because the mean of its divisors is an integer number (278261576376).

Almost surely, 2^{1113043303301} is an apocalyptic number.

It is an amenable number.

1113043303301 is a deficient number, since it is larger than the sum of its proper divisors (3002203).

1113043303301 is an equidigital number, since it uses as much as digits as its factorization.

1113043303301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3002202.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1113043303301 its reverse (1033033403111), we get a palindrome (2146076706412).

The spelling of 1113043303301 in words is "one trillion, one hundred thirteen billion, forty-three million, three hundred three thousand, three hundred one".