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11131031302 = 25565515651
BaseRepresentation
bin10100101110111011…
…00000111100000110
31001201201222222101121
422113131200330012
5140244021000202
65040304344154
7542560130206
oct122735407406
931651888347
1011131031302
1147a21a4626
1221a791505a
131085114671
1477845c406
15452323537
hex297760f06

11131031302 has 4 divisors (see below), whose sum is σ = 16696546956. Its totient is φ = 5565515650.

The previous prime is 11131031293. The next prime is 11131031321. The reversal of 11131031302 is 20313013111.

11131031302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20313013111 = 57373540703.

It is a super-2 number, since 2×111310313022 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2782757824 + ... + 2782757827.

It is an arithmetic number, because the mean of its divisors is an integer number (4174136739).

Almost surely, 211131031302 is an apocalyptic number.

11131031302 is a deficient number, since it is larger than the sum of its proper divisors (5565515654).

11131031302 is an equidigital number, since it uses as much as digits as its factorization.

11131031302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5565515653.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11131031302 its reverse (20313013111), we get a palindrome (31444044413).

The spelling of 11131031302 in words is "eleven billion, one hundred thirty-one million, thirty-one thousand, three hundred two".

Divisors: 1 2 5565515651 11131031302