111311102017 has 2 divisors, whose sum is σ = 111311102018. Its totient is φ = 111311102016.

The previous prime is 111311102009. The next prime is 111311102029. The reversal of 111311102017 is 710201113111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88947694081 + 22363407936 = 298241^2 + 149544^2 .

It is a cyclic number.

It is not a de Polignac number, because 111311102017 - 2³ = 111311102009 is a prime.

It is a super-2 number, since 2×111311102017² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111311101985 and 111311102003.

It is not a weakly prime, because it can be changed into another prime (111311102047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55655551008 + 55655551009.

It is an arithmetic number, because the mean of its divisors is an integer number (55655551009).

Almost surely, 2^111311102017 is an apocalyptic number.

It is an amenable number.

111311102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

111311102017 is an equidigital number, since it uses as much as digits as its factorization.

111311102017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 111311102017 its reverse (710201113111), we get a palindrome (821512215128).

The spelling of 111311102017 in words is "one hundred eleven billion, three hundred eleven million, one hundred two thousand, seventeen".