Base | Representation |
---|---|
bin | 1010000111111010101000… |
… | …0011000101100101101011 |
3 | 1110102010100102021100020002 |
4 | 2201332222003011211223 |
5 | 2424333004434344404 |
6 | 35401321322253215 |
7 | 2226124235041553 |
oct | 241765203054553 |
9 | 43363312240202 |
10 | 11131113199979 |
11 | 3601751239723 |
12 | 12b934b35720b |
13 | 629875b1b7a6 |
14 | 2a6a6a818163 |
15 | 14482c10ec1e |
hex | a1faa0c596b |
11131113199979 has 2 divisors, whose sum is σ = 11131113199980. Its totient is φ = 11131113199978.
The previous prime is 11131113199961. The next prime is 11131113200027. The reversal of 11131113199979 is 97999131113111.
11131113199979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11131113199979 is a prime.
It is not a weakly prime, because it can be changed into another prime (11131113199919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565556599989 + 5565556599990.
It is an arithmetic number, because the mean of its divisors is an integer number (5565556599990).
Almost surely, 211131113199979 is an apocalyptic number.
11131113199979 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131113199979 is an equidigital number, since it uses as much as digits as its factorization.
11131113199979 is an evil number, because the sum of its binary digits is even.
The product of its digits is 413343, while the sum is 56.
The spelling of 11131113199979 in words is "eleven trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred ninety-nine thousand, nine hundred seventy-nine".
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