| Base | Representation |
|---|---|
| bin | 10100101110111011… |
| … | …11001010001111000 |
| 3 | 1001201202012001011010 |
| 4 | 22113131321101320 |
| 5 | 140244032143000 |
| 6 | 5040310433520 |
| 7 | 542561023653 |
| oct | 122735712170 |
| 9 | 31652161133 |
| 10 | 11131131000 |
| 11 | 47a2262520 |
| 12 | 21a79628a0 |
| 13 | 108514ab62 |
| 14 | 77848689a |
| 15 | 452342d50 |
| hex | 297779478 |
11131131000 has 512 divisors, whose sum is σ = 40947379200. Its totient is φ = 2488320000.
The previous prime is 11131130951. The next prime is 11131131001. The reversal of 11131131000 is 13113111.
It is a super-2 number, since 2×111311310002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11131131001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25706784 + ... + 25707216.
It is an arithmetic number, because the mean of its divisors is an integer number (79975350).
Almost surely, 211131131000 is an apocalyptic number.
11131131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11131131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20473689600).
11131131000 is an abundant number, since it is smaller than the sum of its proper divisors (29816248200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11131131000 is a wasteful number, since it uses less digits than its factorization.
11131131000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 528 (or 514 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 12.
Adding to 11131131000 its reverse (13113111), we get a palindrome (11144244111).
It can be divided in two parts, 111311 and 31000, that added together give a triangular number (142311 = T533).
The spelling of 11131131000 in words is "eleven billion, one hundred thirty-one million, one hundred thirty-one thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •