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11131200007 = 172298914923
BaseRepresentation
bin10100101110111100…
…01010001000000111
31001201202022112210221
422113132022020013
5140244041400012
65040312125211
7542561432104
oct122736121007
931652275727
1011131200007
1147a22aa354
1221a7996807
1310851733a5
147784a3aab
15452358507
hex29778a207

11131200007 has 24 divisors (see below), whose sum is σ = 12370503600. Its totient is φ = 10000843776.

The previous prime is 11131199999. The next prime is 11131200011. The reversal of 11131200007 is 70000213111.

It is not a de Polignac number, because 11131200007 - 23 = 11131199999 is a prime.

It is a super-2 number, since 2×111312000072 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11131200077) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 738448 + ... + 753370.

It is an arithmetic number, because the mean of its divisors is an integer number (515437650).

Almost surely, 211131200007 is an apocalyptic number.

11131200007 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

11131200007 is a deficient number, since it is larger than the sum of its proper divisors (1239303593).

11131200007 is a wasteful number, since it uses less digits than its factorization.

11131200007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15075 (or 15058 counting only the distinct ones).

The product of its (nonzero) digits is 42, while the sum is 16.

Adding to 11131200007 its reverse (70000213111), we get a palindrome (81131413118).

The spelling of 11131200007 in words is "eleven billion, one hundred thirty-one million, two hundred thousand, seven".

Divisors: 1 17 29 89 289 493 1513 2581 8381 14923 25721 43877 253691 432767 745909 1328147 4312747 7357039 22578499 38516263 125069663 383834483 654776471 11131200007