111312000202101 has 4 divisors (see below), whose sum is σ = 148416000269472. Its totient is φ = 74208000134732.

The previous prime is 111312000202097. The next prime is 111312000202103. The reversal of 111312000202101 is 101202000213111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111312000202101 - 2² = 111312000202097 is a prime.

It is a super-2 number, since 2×111312000202101² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111312000202103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18552000033681 + ... + 18552000033686.

It is an arithmetic number, because the mean of its divisors is an integer number (37104000067368).

Almost surely, 2^{111312000202101} is an apocalyptic number.

It is an amenable number.

111312000202101 is a deficient number, since it is larger than the sum of its proper divisors (37104000067371).

111312000202101 is an equidigital number, since it uses as much as digits as its factorization.

111312000202101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37104000067370.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 111312000202101 its reverse (101202000213111), we get a palindrome (212514000415212).

The spelling of 111312000202101 in words is "one hundred eleven trillion, three hundred twelve billion, two hundred two thousand, one hundred one".