Base | Representation |
---|---|
bin | 1010000111111011000100… |
… | …1100110111001110101001 |
3 | 1110102010122210002010120121 |
4 | 2201332301030313032221 |
5 | 2424333231144444423 |
6 | 35401341250323241 |
7 | 2226130223045122 |
oct | 241766114671651 |
9 | 43363583063517 |
10 | 11131233203113 |
11 | 3601802a52871 |
12 | 12b9383589521 |
13 | 629894946c6a |
14 | 2a6a7c735049 |
15 | 14483791645d |
hex | a1fb13373a9 |
11131233203113 has 4 divisors (see below), whose sum is σ = 11265344446608. Its totient is φ = 10997121959620.
The previous prime is 11131233203107. The next prime is 11131233203149. The reversal of 11131233203113 is 31130233213111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11131233203113 - 217 = 11131233072041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11131233203183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67055621623 + ... + 67055621788.
It is an arithmetic number, because the mean of its divisors is an integer number (2816336111652).
Almost surely, 211131233203113 is an apocalyptic number.
It is an amenable number.
11131233203113 is a deficient number, since it is larger than the sum of its proper divisors (134111243495).
11131233203113 is an equidigital number, since it uses as much as digits as its factorization.
11131233203113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134111243494.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11131233203113 its reverse (31130233213111), we get a palindrome (42261466416224).
The spelling of 11131233203113 in words is "eleven trillion, one hundred thirty-one billion, two hundred thirty-three million, two hundred three thousand, one hundred thirteen".
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