1113132017 has 2 divisors, whose sum is σ = 1113132018. Its totient is φ = 1113132016.

The previous prime is 1113131963. The next prime is 1113132029. The reversal of 1113132017 is 7102313111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1112822881 + 309136 = 33359^2 + 556^2 .

It is an emirp because it is prime and its reverse (7102313111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113132017 is a prime.

It is a super-4 number, since 4×1113132017⁴ (a number of 37 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1113132017.

It is not a weakly prime, because it can be changed into another prime (1113132077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556566008 + 556566009.

It is an arithmetic number, because the mean of its divisors is an integer number (556566009).

Almost surely, 2^1113132017 is an apocalyptic number.

It is an amenable number.

1113132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113132017 is an equidigital number, since it uses as much as digits as its factorization.

1113132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

The square root of 1113132017 is about 33363.6331504829. The cubic root of 1113132017 is about 1036.3717307787.

Adding to 1113132017 its reverse (7102313111), we get a palindrome (8215445128).

The spelling of 1113132017 in words is "one billion, one hundred thirteen million, one hundred thirty-two thousand, seventeen".