Base | Representation |
---|---|
bin | 1010000111111011101100… |
… | …1111110000010101101011 |
3 | 1110102011002112012100210011 |
4 | 2201332323033300111223 |
5 | 2424334102320432413 |
6 | 35401410110432351 |
7 | 2226134340403243 |
oct | 241767317602553 |
9 | 43364075170704 |
10 | 11131401733483 |
11 | 360188a0a1169 |
12 | 12b940bb026b7 |
13 | 6298c0833385 |
14 | 2a6a96c84b23 |
15 | 14484760633d |
hex | a1fbb3f056b |
11131401733483 has 2 divisors, whose sum is σ = 11131401733484. Its totient is φ = 11131401733482.
The previous prime is 11131401733381. The next prime is 11131401733531. The reversal of 11131401733483 is 38433710413111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11131401733483 - 237 = 10993962780011 is a prime.
It is a super-2 number, since 2×111314017334832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11131401733183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565700866741 + 5565700866742.
It is an arithmetic number, because the mean of its divisors is an integer number (5565700866742).
Almost surely, 211131401733483 is an apocalyptic number.
11131401733483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131401733483 is an equidigital number, since it uses as much as digits as its factorization.
11131401733483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 11131401733483 in words is "eleven trillion, one hundred thirty-one billion, four hundred one million, seven hundred thirty-three thousand, four hundred eighty-three".
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