Base | Representation |
---|---|
bin | 1010000111111011110001… |
… | …0101111100101110110011 |
3 | 1110102011010210211012222202 |
4 | 2201332330111330232303 |
5 | 2424334122023244243 |
6 | 35401412005053415 |
7 | 2226134652662066 |
oct | 241767425745663 |
9 | 43364123735882 |
10 | 11131420134323 |
11 | 3601899519a75 |
12 | 12b94160b726b |
13 | 6298c45a6948 |
14 | 2a6a994b48dd |
15 | 14484903d4b8 |
hex | a1fbc57cbb3 |
11131420134323 has 2 divisors, whose sum is σ = 11131420134324. Its totient is φ = 11131420134322.
The previous prime is 11131420134277. The next prime is 11131420134353. The reversal of 11131420134323 is 32343102413111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11131420134323 - 220 = 11131419085747 is a prime.
It is a super-2 number, since 2×111314201343232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11131420134353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565710067161 + 5565710067162.
It is an arithmetic number, because the mean of its divisors is an integer number (5565710067162).
Almost surely, 211131420134323 is an apocalyptic number.
11131420134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131420134323 is an equidigital number, since it uses as much as digits as its factorization.
11131420134323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 11131420134323 its reverse (32343102413111), we get a palindrome (43474522547434).
The spelling of 11131420134323 in words is "eleven trillion, one hundred thirty-one billion, four hundred twenty million, one hundred thirty-four thousand, three hundred twenty-three".
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