Base | Representation |
---|---|
bin | 10000001100110001000… |
… | …101101111111110001001 |
3 | 10221102102020001110200202 |
4 | 100030301011233332021 |
5 | 121214333322323312 |
6 | 2211223430341545 |
7 | 143266426616534 |
oct | 20146105577611 |
9 | 3842366043622 |
10 | 1113220120457 |
11 | 39a128811185 |
12 | 15b8bb1ba8b5 |
13 | 80c8c95a463 |
14 | 3bc47171a1b |
15 | 1de563d39c2 |
hex | 1033116ff89 |
1113220120457 has 2 divisors, whose sum is σ = 1113220120458. Its totient is φ = 1113220120456.
The previous prime is 1113220120403. The next prime is 1113220120487. The reversal of 1113220120457 is 7540210223111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 572449612816 + 540770507641 = 756604^2 + 735371^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113220120457 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113220120487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556610060228 + 556610060229.
It is an arithmetic number, because the mean of its divisors is an integer number (556610060229).
Almost surely, 21113220120457 is an apocalyptic number.
It is an amenable number.
1113220120457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113220120457 is an equidigital number, since it uses as much as digits as its factorization.
1113220120457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360, while the sum is 29.
Adding to 1113220120457 its reverse (7540210223111), we get a palindrome (8653430343568).
The spelling of 1113220120457 in words is "one trillion, one hundred thirteen billion, two hundred twenty million, one hundred twenty thousand, four hundred fifty-seven".
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