1113220441141 has 4 divisors (see below), whose sum is σ = 1149130777984. Its totient is φ = 1077310104300.

The previous prime is 1113220441129. The next prime is 1113220441159. The reversal of 1113220441141 is 1411440223111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113220441141 is a prime.

It is a super-3 number, since 3×1113220441141³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113220441111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17955168375 + ... + 17955168436.

It is an arithmetic number, because the mean of its divisors is an integer number (287282694496).

Almost surely, 2^{1113220441141} is an apocalyptic number.

It is an amenable number.

1113220441141 is a deficient number, since it is larger than the sum of its proper divisors (35910336843).

1113220441141 is an equidigital number, since it uses as much as digits as its factorization.

1113220441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35910336842.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1113220441141 its reverse (1411440223111), we get a palindrome (2524660664252).

The spelling of 1113220441141 in words is "one trillion, one hundred thirteen billion, two hundred twenty million, four hundred forty-one thousand, one hundred forty-one".