Base | Representation |
---|---|
bin | 1010000111111111000011… |
… | …0010100111101111011001 |
3 | 1110102020102010120100222201 |
4 | 2201333300302213233121 |
5 | 2424342422304101003 |
6 | 35402035201050201 |
7 | 2226165526164616 |
oct | 241776062475731 |
9 | 43366363510881 |
10 | 11132300065753 |
11 | 3602200194529 |
12 | 12b9620926961 |
13 | 629a04994929 |
14 | 2a6b402c950d |
15 | 14489b403b1d |
hex | a1ff0ca7bd9 |
11132300065753 has 2 divisors, whose sum is σ = 11132300065754. Its totient is φ = 11132300065752.
The previous prime is 11132300065739. The next prime is 11132300065781. The reversal of 11132300065753 is 35756000323111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10357120189504 + 775179876249 = 3218248^2 + 880443^2 .
It is a cyclic number.
It is not a de Polignac number, because 11132300065753 - 213 = 11132300057561 is a prime.
It is not a weakly prime, because it can be changed into another prime (11132300065553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566150032876 + 5566150032877.
It is an arithmetic number, because the mean of its divisors is an integer number (5566150032877).
Almost surely, 211132300065753 is an apocalyptic number.
It is an amenable number.
11132300065753 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132300065753 is an equidigital number, since it uses as much as digits as its factorization.
11132300065753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 37.
Adding to 11132300065753 its reverse (35756000323111), we get a palindrome (46888300388864).
The spelling of 11132300065753 in words is "eleven trillion, one hundred thirty-two billion, three hundred million, sixty-five thousand, seven hundred fifty-three".
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