Base | Representation |
---|---|
bin | 1010000111111111001010… |
… | …1101111101110110011011 |
3 | 1110102020111101102010021102 |
4 | 2201333302231331312123 |
5 | 2424343004043300102 |
6 | 35402042314102015 |
7 | 2226166401054626 |
oct | 241776255756633 |
9 | 43366441363242 |
10 | 11132332400027 |
11 | 3602217469773 |
12 | 12b962b71a90b |
13 | 629a0b5a6237 |
14 | 2a6b44704dbd |
15 | 14489e18e402 |
hex | a1ff2b7dd9b |
11132332400027 has 2 divisors, whose sum is σ = 11132332400028. Its totient is φ = 11132332400026.
The previous prime is 11132332399927. The next prime is 11132332400047. The reversal of 11132332400027 is 72000423323111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11132332400027 is a prime.
It is not a weakly prime, because it can be changed into another prime (11132332400047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566166200013 + 5566166200014.
It is an arithmetic number, because the mean of its divisors is an integer number (5566166200014).
Almost surely, 211132332400027 is an apocalyptic number.
11132332400027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132332400027 is an equidigital number, since it uses as much as digits as its factorization.
11132332400027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 11132332400027 its reverse (72000423323111), we get a palindrome (83132755723138).
The spelling of 11132332400027 in words is "eleven trillion, one hundred thirty-two billion, three hundred thirty-two million, four hundred thousand, twenty-seven".
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