Base | Representation |
---|---|
bin | 10100101111000101… |
… | …11000111010101010 |
3 | 1001201211122120002021 |
4 | 22113202320322222 |
5 | 140244401041414 |
6 | 5040354455054 |
7 | 542605115656 |
oct | 122742707252 |
9 | 31654576067 |
10 | 11132440234 |
11 | 47a2a77133 |
12 | 21a829448a |
13 | 10854b8a56 |
14 | 778707a66 |
15 | 452500c24 |
hex | 2978b8eaa |
11132440234 has 4 divisors (see below), whose sum is σ = 16698660354. Its totient is φ = 5566220116.
The previous prime is 11132440217. The next prime is 11132440261. The reversal of 11132440234 is 43204423111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43204423111 = 431 ⋅100242281.
It can be written as a sum of positive squares in only one way, i.e., 10771326225 + 361114009 = 103785^2 + 19003^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11132440199 and 11132440208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2783110057 + ... + 2783110060.
Almost surely, 211132440234 is an apocalyptic number.
11132440234 is a deficient number, since it is larger than the sum of its proper divisors (5566220120).
11132440234 is an equidigital number, since it uses as much as digits as its factorization.
11132440234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5566220119.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 11132440234 its reverse (43204423111), we get a palindrome (54336863345).
The spelling of 11132440234 in words is "eleven billion, one hundred thirty-two million, four hundred forty thousand, two hundred thirty-four".
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