Base | Representation |
---|---|
bin | 10100101111001010… |
… | …11001111111110111 |
3 | 1001201212220002010220 |
4 | 22113211121333313 |
5 | 140300033200043 |
6 | 5040420545423 |
7 | 542613534363 |
oct | 122745317767 |
9 | 31655802126 |
10 | 11133100023 |
11 | 47a3387911 |
12 | 21a8552273 |
13 | 108568a166 |
14 | 77883a2a3 |
15 | 4525d1483 |
hex | 297959ff7 |
11133100023 has 8 divisors (see below), whose sum is σ = 15124211568. Its totient is φ = 7282027584.
The previous prime is 11133100009. The next prime is 11133100037. The reversal of 11133100023 is 32000133111.
It is an interprime number because it is at equal distance from previous prime (11133100009) and next prime (11133100037).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11133100023 - 213 = 11133091831 is a prime.
It is a super-2 number, since 2×111331000232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11133099975 and 11133100011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11133100003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35009590 + ... + 35009907.
It is an arithmetic number, because the mean of its divisors is an integer number (1890526446).
Almost surely, 211133100023 is an apocalyptic number.
11133100023 is a deficient number, since it is larger than the sum of its proper divisors (3991111545).
11133100023 is an equidigital number, since it uses as much as digits as its factorization.
11133100023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70019553.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11133100023 its reverse (32000133111), we get a palindrome (43133233134).
It can be divided in two parts, 11133 and 100023, that added together give a triangular number (111156 = T471).
The spelling of 11133100023 in words is "eleven billion, one hundred thirty-three million, one hundred thousand, twenty-three".
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