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1113311030102 = 2556655515051
BaseRepresentation
bin10000001100110110100…
…000100010101101010110
310221102122120010011021122
4100030312200202231112
5121220030110430402
62211240435043542
7143301612421325
oct20146640425526
93842576104248
101113311030102
1139a175063a17
1215b9257405b2
1380ca573a44b
143bc552780bc
151de5e38eca2
hex10336822b56

1113311030102 has 4 divisors (see below), whose sum is σ = 1669966545156. Its totient is φ = 556655515050.

The previous prime is 1113311030101. The next prime is 1113311030107. The reversal of 1113311030102 is 2010301133111.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11133110301022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113311030101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278327757524 + ... + 278327757527.

It is an arithmetic number, because the mean of its divisors is an integer number (417491636289).

Almost surely, 21113311030102 is an apocalyptic number.

1113311030102 is a deficient number, since it is larger than the sum of its proper divisors (556655515054).

1113311030102 is an equidigital number, since it uses as much as digits as its factorization.

1113311030102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556655515053.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1113311030102 its reverse (2010301133111), we get a palindrome (3123612163213).

The spelling of 1113311030102 in words is "one trillion, one hundred thirteen billion, three hundred eleven million, thirty thousand, one hundred two".

Divisors: 1 2 556655515051 1113311030102