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11133123000 = 2335331592029
BaseRepresentation
bin10100101111001010…
…11111100110111000
31001201212221020122220
422113211133212320
5140300034414000
65040421244040
7542613661356
oct122745374670
931655836586
1011133123000
1147a33a30aa
1221a8563620
13108569775c
147788447d6
154525d81a0
hex29795f9b8

11133123000 has 256 divisors, whose sum is σ = 36481536000. Its totient is φ = 2822976000.

The previous prime is 11133122983. The next prime is 11133123011. The reversal of 11133123000 is 32133111.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5485986 + ... + 5488014.

It is an arithmetic number, because the mean of its divisors is an integer number (142506000).

Almost surely, 211133123000 is an apocalyptic number.

11133123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11133123000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18240768000).

11133123000 is an abundant number, since it is smaller than the sum of its proper divisors (25348413000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11133123000 is a wasteful number, since it uses less digits than its factorization.

11133123000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2143 (or 2129 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11133123000 its reverse (32133111), we get a palindrome (11165256111).

The spelling of 11133123000 in words is "eleven billion, one hundred thirty-three million, one hundred twenty-three thousand".