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11133231310147 is a prime number
BaseRepresentation
bin1010001000000010100001…
…0011000010010101000011
31110102022211000212111010211
42202000220103002111003
52424401324203411042
635402311424534551
72226230564504062
oct242005023022503
943368730774124
1011133231310147
1136026389171a1
1212b9840781457
13629b228aa80b
142a6bcbc5a1d9
15144903053017
hexa20284c2543

11133231310147 has 2 divisors, whose sum is σ = 11133231310148. Its totient is φ = 11133231310146.

The previous prime is 11133231310121. The next prime is 11133231310153. The reversal of 11133231310147 is 74101313233111.

It is a strong prime.

It is an emirp because it is prime and its reverse (74101313233111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11133231310147 - 211 = 11133231308099 is a prime.

It is a super-2 number, since 2×111332313101472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11133231310447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566615655073 + 5566615655074.

It is an arithmetic number, because the mean of its divisors is an integer number (5566615655074).

Almost surely, 211133231310147 is an apocalyptic number.

11133231310147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133231310147 is an equidigital number, since it uses as much as digits as its factorization.

11133231310147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 31.

Adding to 11133231310147 its reverse (74101313233111), we get a palindrome (85234544543258).

The spelling of 11133231310147 in words is "eleven trillion, one hundred thirty-three billion, two hundred thirty-one million, three hundred ten thousand, one hundred forty-seven".