Base | Representation |
---|---|
bin | 10000001100110111101… |
… | …001010100111000110011 |
3 | 10221102200220000111222122 |
4 | 100030313221110320303 |
5 | 121220100002010003 |
6 | 2211242400024455 |
7 | 143302233536006 |
oct | 20146751247063 |
9 | 3842626014878 |
10 | 1113330110003 |
11 | 39a184905a31 |
12 | 15b93000212b |
13 | 80ca968ab27 |
14 | 3bc57a0353d |
15 | 1de60dad238 |
hex | 10337a54e33 |
1113330110003 has 2 divisors, whose sum is σ = 1113330110004. Its totient is φ = 1113330110002.
The previous prime is 1113330109999. The next prime is 1113330110017. The reversal of 1113330110003 is 3000110333111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113330110003 - 22 = 1113330109999 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113330110033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665055001 + 556665055002.
It is an arithmetic number, because the mean of its divisors is an integer number (556665055002).
Almost surely, 21113330110003 is an apocalyptic number.
1113330110003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113330110003 is an equidigital number, since it uses as much as digits as its factorization.
1113330110003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1113330110003 its reverse (3000110333111), we get a palindrome (4113440443114).
The spelling of 1113330110003 in words is "one trillion, one hundred thirteen billion, three hundred thirty million, one hundred ten thousand, three".
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