Base | Representation |
---|---|
bin | 1010001000000010110100… |
… | …0111111111010001010001 |
3 | 1110102100000200021012111012 |
4 | 2202000231013333101101 |
5 | 2424402010422100423 |
6 | 35402323440500305 |
7 | 2226232600062323 |
oct | 242005507772121 |
9 | 43370020235435 |
10 | 11133312300113 |
11 | 360267a604153 |
12 | 12b986391a695 |
13 | 629b365c6683 |
14 | 2a6bd88dd613 |
15 | 14490a200078 |
hex | a202d1ff451 |
11133312300113 has 2 divisors, whose sum is σ = 11133312300114. Its totient is φ = 11133312300112.
The previous prime is 11133312300083. The next prime is 11133312300139. The reversal of 11133312300113 is 31100321333111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6141336461584 + 4991975838529 = 2478172^2 + 2234273^2 .
It is an emirp because it is prime and its reverse (31100321333111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11133312300113 - 212 = 11133312296017 is a prime.
It is not a weakly prime, because it can be changed into another prime (11133312300193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566656150056 + 5566656150057.
It is an arithmetic number, because the mean of its divisors is an integer number (5566656150057).
Almost surely, 211133312300113 is an apocalyptic number.
It is an amenable number.
11133312300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133312300113 is an equidigital number, since it uses as much as digits as its factorization.
11133312300113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11133312300113 its reverse (31100321333111), we get a palindrome (42233633633224).
The spelling of 11133312300113 in words is "eleven trillion, one hundred thirty-three billion, three hundred twelve million, three hundred thousand, one hundred thirteen".
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