1113331431257 has 2 divisors, whose sum is σ = 1113331431258. Its totient is φ = 1113331431256.

The previous prime is 1113331431241. The next prime is 1113331431263. The reversal of 1113331431257 is 7521341333111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 794444211856 + 318887219401 = 891316^2 + 564701^2 .

It is an emirp because it is prime and its reverse (7521341333111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113331431257 - 2⁴ = 1113331431241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113331431217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665715628 + 556665715629.

It is an arithmetic number, because the mean of its divisors is an integer number (556665715629).

Almost surely, 2^{1113331431257} is an apocalyptic number.

It is an amenable number.

1113331431257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113331431257 is an equidigital number, since it uses as much as digits as its factorization.

1113331431257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 22680, while the sum is 35.

Adding to 1113331431257 its reverse (7521341333111), we get a palindrome (8634672764368).

The spelling of 1113331431257 in words is "one trillion, one hundred thirteen billion, three hundred thirty-one million, four hundred thirty-one thousand, two hundred fifty-seven".