Base | Representation |
---|---|
bin | 10000001100110111101… |
… | …110010111011110001011 |
3 | 10221102200222111122110211 |
4 | 100030313232113132023 |
5 | 121220100321300212 |
6 | 2211242444221551 |
7 | 143302251011134 |
oct | 20146756273613 |
9 | 3842628448424 |
10 | 1113331431307 |
11 | 39a185628717 |
12 | 15b93053a8b7 |
13 | 80ca9a31374 |
14 | 3bc57c68c8b |
15 | 1de6106e9a7 |
hex | 10337b9778b |
1113331431307 has 2 divisors, whose sum is σ = 1113331431308. Its totient is φ = 1113331431306.
The previous prime is 1113331431263. The next prime is 1113331431347. The reversal of 1113331431307 is 7031341333111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113331431307 - 219 = 1113330907019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113331431347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665715653 + 556665715654.
It is an arithmetic number, because the mean of its divisors is an integer number (556665715654).
Almost surely, 21113331431307 is an apocalyptic number.
1113331431307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113331431307 is an equidigital number, since it uses as much as digits as its factorization.
1113331431307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 1113331431307 its reverse (7031341333111), we get a palindrome (8144672764418).
The spelling of 1113331431307 in words is "one trillion, one hundred thirteen billion, three hundred thirty-one million, four hundred thirty-one thousand, three hundred seven".
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