Base | Representation |
---|---|
bin | 1010001000000010110110… |
… | …1001001001001101000001 |
3 | 1110102100001021121202220101 |
4 | 2202000231221021031001 |
5 | 2424402020133212203 |
6 | 35402324351042401 |
7 | 2226233034001645 |
oct | 242005551111501 |
9 | 43370037552811 |
10 | 11133320991553 |
11 | 3602684500162 |
12 | 12b9866810401 |
13 | 629b3834a737 |
14 | 2a6bd9b22c25 |
15 | 14490ad6a41d |
hex | a202da49341 |
11133320991553 has 2 divisors, whose sum is σ = 11133320991554. Its totient is φ = 11133320991552.
The previous prime is 11133320991517. The next prime is 11133320991593. The reversal of 11133320991553 is 35519902333111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10138218979249 + 995102012304 = 3184057^2 + 997548^2 .
It is a cyclic number.
It is not a de Polignac number, because 11133320991553 - 237 = 10995882038081 is a prime.
It is not a weakly prime, because it can be changed into another prime (11133320991593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566660495776 + 5566660495777.
It is an arithmetic number, because the mean of its divisors is an integer number (5566660495777).
Almost surely, 211133320991553 is an apocalyptic number.
It is an amenable number.
11133320991553 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133320991553 is an equidigital number, since it uses as much as digits as its factorization.
11133320991553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 328050, while the sum is 46.
The spelling of 11133320991553 in words is "eleven trillion, one hundred thirty-three billion, three hundred twenty million, nine hundred ninety-one thousand, five hundred fifty-three".
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