1113340433111 has 4 divisors (see below), whose sum is σ = 1117479245400. Its totient is φ = 1109201620824.

The previous prime is 1113340433077. The next prime is 1113340433113.

1113340433111 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113340433111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113340433113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2069405741 + ... + 2069406278.

It is an arithmetic number, because the mean of its divisors is an integer number (279369811350).

Almost surely, 2^{1113340433111} is an apocalyptic number.

1113340433111 is a deficient number, since it is larger than the sum of its proper divisors (4138812289).

1113340433111 is an equidigital number, since it uses as much as digits as its factorization.

1113340433111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4138812288.

The product of its (nonzero) digits is 1296, while the sum is 26.

It can be divided in two parts, 1113340 and 433111, that added together give a palindrome (1546451).

The spelling of 1113340433111 in words is "one trillion, one hundred thirteen billion, three hundred forty million, four hundred thirty-three thousand, one hundred eleven".