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11133433122 = 237265081741
BaseRepresentation
bin10100101111001101…
…01011010100100010
31001201220112000001220
422113212223110202
5140300124324442
65040432035510
7542616422460
oct122746532442
931656460056
1011133433122
1147a35950a9
1221a8692b96
131085775966
147788c5830
15452649eec
hex2979ab522

11133433122 has 16 divisors (see below), whose sum is σ = 25447847232. Its totient is φ = 3180980880.

The previous prime is 11133433121. The next prime is 11133433177. The reversal of 11133433122 is 22133433111.

11133433122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11133433092 and 11133433101.

It is not an unprimeable number, because it can be changed into a prime (11133433121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132540829 + ... + 132540912.

It is an arithmetic number, because the mean of its divisors is an integer number (1590490452).

Almost surely, 211133433122 is an apocalyptic number.

11133433122 is an abundant number, since it is smaller than the sum of its proper divisors (14314414110).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11133433122 is a wasteful number, since it uses less digits than its factorization.

11133433122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 265081753.

The product of its digits is 1296, while the sum is 24.

Adding to 11133433122 its reverse (22133433111), we get a palindrome (33266866233).

The spelling of 11133433122 in words is "eleven billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred twenty-two".

Divisors: 1 2 3 6 7 14 21 42 265081741 530163482 795245223 1590490446 1855572187 3711144374 5566716561 11133433122