Base | Representation |
---|---|
bin | 1010001000000011100011… |
… | …1111001101011010010111 |
3 | 1110102100112112202201202201 |
4 | 2202000320333031122113 |
5 | 2424402412344402320 |
6 | 35402355310345331 |
7 | 2226240534546640 |
oct | 242007077153227 |
9 | 43370475681681 |
10 | 11133511325335 |
11 | 3602771990803 |
12 | 12b98ba4bb247 |
13 | 629b688cc089 |
14 | 2a6c1710a6c7 |
15 | 14491c91570a |
hex | a2038fcd697 |
11133511325335 has 16 divisors (see below), whose sum is σ = 15290912259072. Its totient is φ = 7623359402400.
The previous prime is 11133511325303. The next prime is 11133511325381. The reversal of 11133511325335 is 53352311533111.
It is a happy number.
11133511325335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11133511325335 - 25 = 11133511325303 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11133511325294 and 11133511325303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 230149711 + ... + 230198080.
It is an arithmetic number, because the mean of its divisors is an integer number (955682016192).
Almost surely, 211133511325335 is an apocalyptic number.
11133511325335 is a deficient number, since it is larger than the sum of its proper divisors (4157400933737).
11133511325335 is an equidigital number, since it uses as much as digits as its factorization.
11133511325335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 460348494.
The product of its digits is 60750, while the sum is 37.
Adding to 11133511325335 its reverse (53352311533111), we get a palindrome (64485822858446).
The spelling of 11133511325335 in words is "eleven trillion, one hundred thirty-three billion, five hundred eleven million, three hundred twenty-five thousand, three hundred thirty-five".
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