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11133544434134 = 25566772217067
BaseRepresentation
bin1010001000000011101011…
…1101100000100111010110
31110102100121212001211111112
42202000322331200213112
52424402444333343014
635402402452135022
72226241416144023
oct242007275404726
943370555054445
1011133544434134
113602789644951
1212b9909607472
13629b72722095
142a6c1b68854a
151449207a573e
hexa203af609d6

11133544434134 has 4 divisors (see below), whose sum is σ = 16700316651204. Its totient is φ = 5566772217066.

The previous prime is 11133544434113. The next prime is 11133544434137. The reversal of 11133544434134 is 43143444533111.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 11133544434091 and 11133544434100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11133544434137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2783386108532 + ... + 2783386108535.

It is an arithmetic number, because the mean of its divisors is an integer number (4175079162801).

Almost surely, 211133544434134 is an apocalyptic number.

11133544434134 is a deficient number, since it is larger than the sum of its proper divisors (5566772217070).

11133544434134 is an equidigital number, since it uses as much as digits as its factorization.

11133544434134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5566772217069.

The product of its digits is 414720, while the sum is 41.

Adding to 11133544434134 its reverse (43143444533111), we get a palindrome (54276988967245).

The spelling of 11133544434134 in words is "eleven trillion, one hundred thirty-three billion, five hundred forty-four million, four hundred thirty-four thousand, one hundred thirty-four".

Divisors: 1 2 5566772217067 11133544434134