Base | Representation |
---|---|
bin | 10000001100111010000… |
… | …011001100001011000001 |
3 | 10221102210200220201111012 |
4 | 100030322003030023001 |
5 | 121220140313210411 |
6 | 2211250400330305 |
7 | 143303233426151 |
oct | 20147203141301 |
9 | 3842720821435 |
10 | 1113370444481 |
11 | 39a1a5654909 |
12 | 15b941613995 |
13 | 80cb4b40999 |
14 | 3bc5d102761 |
15 | 1de646c918b |
hex | 1033a0cc2c1 |
1113370444481 has 2 divisors, whose sum is σ = 1113370444482. Its totient is φ = 1113370444480.
The previous prime is 1113370444399. The next prime is 1113370444519. The reversal of 1113370444481 is 1844440733111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 917028403456 + 196342041025 = 957616^2 + 443105^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113370444481 - 238 = 838492537537 is a prime.
It is a super-2 number, since 2×11133704444812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1113370443481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556685222240 + 556685222241.
It is an arithmetic number, because the mean of its divisors is an integer number (556685222241).
Almost surely, 21113370444481 is an apocalyptic number.
It is an amenable number.
1113370444481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113370444481 is an equidigital number, since it uses as much as digits as its factorization.
1113370444481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129024, while the sum is 41.
The spelling of 1113370444481 in words is "one trillion, one hundred thirteen billion, three hundred seventy million, four hundred forty-four thousand, four hundred eighty-one".
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