1113404201431 has 4 divisors (see below), whose sum is σ = 1120876713000. Its totient is φ = 1105931689864.

The previous prime is 1113404201423. The next prime is 1113404201461. The reversal of 1113404201431 is 1341024043111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113404201431 - 2³ = 1113404201423 is a prime.

It is a super-2 number, since 2×1113404201431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113404201396 and 1113404201405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113404201401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3736255561 + ... + 3736255858.

It is an arithmetic number, because the mean of its divisors is an integer number (280219178250).

Almost surely, 2^{1113404201431} is an apocalyptic number.

1113404201431 is a deficient number, since it is larger than the sum of its proper divisors (7472511569).

1113404201431 is an equidigital number, since it uses as much as digits as its factorization.

1113404201431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7472511568.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1113404201431 its reverse (1341024043111), we get a palindrome (2454428244542).

The spelling of 1113404201431 in words is "one trillion, one hundred thirteen billion, four hundred four million, two hundred one thousand, four hundred thirty-one".