1113404331013 has 4 divisors (see below), whose sum is σ = 1199050818028. Its totient is φ = 1027757844000.

The previous prime is 1113404331001. The next prime is 1113404331043. The reversal of 1113404331013 is 3101334043111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 194906356324 + 918497974689 = 441482^2 + 958383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113404331013 is a prime.

It is a super-3 number, since 3×1113404331013³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113404331043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42823243488 + ... + 42823243513.

It is an arithmetic number, because the mean of its divisors is an integer number (299762704507).

Almost surely, 2^{1113404331013} is an apocalyptic number.

1113404331013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1113404331013 is a deficient number, since it is larger than the sum of its proper divisors (85646487015).

1113404331013 is an equidigital number, since it uses as much as digits as its factorization.

1113404331013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85646487014.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1113404331013 its reverse (3101334043111), we get a palindrome (4214738374124).

The spelling of 1113404331013 in words is "one trillion, one hundred thirteen billion, four hundred four million, three hundred thirty-one thousand, thirteen".