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1113411015001 is a prime number
BaseRepresentation
bin10000001100111100011…
…101111101000101011001
310221102220112020220210001
4100030330131331011121
5121220231204440001
62211254410053001
7143304235321435
oct20147435750531
93842815226701
101113411015001
1139a21654506a
1215b95311a161
1380cc03770cc
143bc646639c5
151de68040001
hex1033c77d159

1113411015001 has 2 divisors, whose sum is σ = 1113411015002. Its totient is φ = 1113411015000.

The previous prime is 1113411014987. The next prime is 1113411015019. The reversal of 1113411015001 is 1005101143111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1042614577225 + 70796437776 = 1021085^2 + 266076^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113411015001 - 27 = 1113411014873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1113411015001.

It is not a weakly prime, because it can be changed into another prime (1113411015071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556705507500 + 556705507501.

It is an arithmetic number, because the mean of its divisors is an integer number (556705507501).

Almost surely, 21113411015001 is an apocalyptic number.

It is an amenable number.

1113411015001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113411015001 is an equidigital number, since it uses as much as digits as its factorization.

1113411015001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 1113411015001 its reverse (1005101143111), we get a palindrome (2118512158112).

The spelling of 1113411015001 in words is "one trillion, one hundred thirteen billion, four hundred eleven million, fifteen thousand, one".