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11134121433 = 33711373811
BaseRepresentation
bin10100101111010010…
…10011010111011001
31001201221210222020220
422113221103113121
5140300313341213
65040454510253
7542625320301
oct122751232731
931657728226
1011134121433
1147a3a15256
1221a8965389
131085957046
14778a24601
15452733e23
hex297a535d9

11134121433 has 4 divisors (see below), whose sum is σ = 14845495248. Its totient is φ = 7422747620.

The previous prime is 11134121393. The next prime is 11134121443. The reversal of 11134121433 is 33412143111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11134121433 - 232 = 6839154137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11134121443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855686903 + ... + 1855686908.

It is an arithmetic number, because the mean of its divisors is an integer number (3711373812).

Almost surely, 211134121433 is an apocalyptic number.

It is an amenable number.

11134121433 is a deficient number, since it is larger than the sum of its proper divisors (3711373815).

11134121433 is an equidigital number, since it uses as much as digits as its factorization.

11134121433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3711373814.

The product of its digits is 864, while the sum is 24.

Adding to 11134121433 its reverse (33412143111), we get a palindrome (44546264544).

The spelling of 11134121433 in words is "eleven billion, one hundred thirty-four million, one hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 3 3711373811 11134121433