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11134221300 = 223252372391399
BaseRepresentation
bin10100101111010011…
…01011101111110100
31001201222000001020200
422113221223233310
5140300330040200
65040501000500
7542626214406
oct122751535764
931658001220
1011134221300
1147a3a83294
1221a89b3130
131085990637
14778a4cb76
15452753800
hex297a6bbf4

11134221300 has 216 divisors, whose sum is σ = 36018528000. Its totient is φ = 2874735360.

The previous prime is 11134221253. The next prime is 11134221313. The reversal of 11134221300 is 312243111.

11134221300 is a `hidden beast` number, since 1 + 1 + 1 + 342 + 21 + 300 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 7958001 + ... + 7959399.

Almost surely, 211134221300 is an apocalyptic number.

11134221300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11134221300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18009264000).

11134221300 is an abundant number, since it is smaller than the sum of its proper divisors (24884306700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11134221300 is a wasteful number, since it uses less digits than its factorization.

11134221300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1695 (or 1685 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11134221300 its reverse (312243111), we get a palindrome (11446464411).

The spelling of 11134221300 in words is "eleven billion, one hundred thirty-four million, two hundred twenty-one thousand, three hundred".