Base | Representation |
---|---|
bin | 10000001100111101100… |
… | …111101011011001100001 |
3 | 10221102221212121210100211 |
4 | 100030331213223121201 |
5 | 121220301131404332 |
6 | 2211300340214121 |
7 | 143304561513205 |
oct | 20147547533141 |
9 | 3842855553324 |
10 | 1113430341217 |
11 | 39a226445147 |
12 | 15b95969a341 |
13 | 80cc438293c |
14 | 3bc67054b05 |
15 | 1de69aab447 |
hex | 1033d9eb661 |
1113430341217 has 2 divisors, whose sum is σ = 1113430341218. Its totient is φ = 1113430341216.
The previous prime is 1113430341197. The next prime is 1113430341227. The reversal of 1113430341217 is 7121430343111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 739022192896 + 374408148321 = 859664^2 + 611889^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113430341217 - 219 = 1113429816929 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113430341227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556715170608 + 556715170609.
It is an arithmetic number, because the mean of its divisors is an integer number (556715170609).
Almost surely, 21113430341217 is an apocalyptic number.
It is an amenable number.
1113430341217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113430341217 is an equidigital number, since it uses as much as digits as its factorization.
1113430341217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1113430341217 its reverse (7121430343111), we get a palindrome (8234860684328).
The spelling of 1113430341217 in words is "one trillion, one hundred thirteen billion, four hundred thirty million, three hundred forty-one thousand, two hundred seventeen".
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