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11134320214111 = 15173737219961
BaseRepresentation
bin1010001000000110100100…
…1100111000000001011111
31110102102121220211112120021
42202001221030320001133
52424411041433322421
635403011443533011
72226266556154153
oct242015114700137
943372556745507
1011134320214111
113603047542926
1212b9aa538a167
13629c67374aa3
142a6c9270b063
15144968946341
hexa206933805f

11134320214111 has 4 divisors (see below), whose sum is σ = 11208057434224. Its totient is φ = 11060582994000.

The previous prime is 11134320214067. The next prime is 11134320214153. The reversal of 11134320214111 is 11141202343111.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-11134320214111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11134320214711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36868609830 + ... + 36868610131.

It is an arithmetic number, because the mean of its divisors is an integer number (2802014358556).

Almost surely, 211134320214111 is an apocalyptic number.

11134320214111 is a deficient number, since it is larger than the sum of its proper divisors (73737220113).

11134320214111 is an equidigital number, since it uses as much as digits as its factorization.

11134320214111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73737220112.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 11134320214111 its reverse (11141202343111), we get a palindrome (22275522557222).

The spelling of 11134320214111 in words is "eleven trillion, one hundred thirty-four billion, three hundred twenty million, two hundred fourteen thousand, one hundred eleven".

Divisors: 1 151 73737219961 11134320214111