1113434150417 has 2 divisors, whose sum is σ = 1113434150418. Its totient is φ = 1113434150416.

The previous prime is 1113434150341. The next prime is 1113434150471. The reversal of 1113434150417 is 7140514343111.

Together with next prime (1113434150471) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1099822028176 + 13612122241 = 1048724^2 + 116671^2 .

It is an emirp because it is prime and its reverse (7140514343111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113434150417 - 2³⁴ = 1096254281233 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113434110417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556717075208 + 556717075209.

It is an arithmetic number, because the mean of its divisors is an integer number (556717075209).

Almost surely, 2^{1113434150417} is an apocalyptic number.

It is an amenable number.

1113434150417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113434150417 is an equidigital number, since it uses as much as digits as its factorization.

1113434150417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 35.

Adding to 1113434150417 its reverse (7140514343111), we get a palindrome (8253948493528).

The spelling of 1113434150417 in words is "one trillion, one hundred thirteen billion, four hundred thirty-four million, one hundred fifty thousand, four hundred seventeen".