Base | Representation |
---|---|
bin | 10000001100111101110… |
… | …110011010100011111111 |
3 | 10221102222010220001200020 |
4 | 100030331312122203333 |
5 | 121220303124020130 |
6 | 2211300555103223 |
7 | 143304636403161 |
oct | 20147566324377 |
9 | 3842863801606 |
10 | 1113434204415 |
11 | 39a228643675 |
12 | 15b95aa41b13 |
13 | 80cc5106160 |
14 | 3bc6777c931 |
15 | 1de6a0c0e10 |
hex | 1033dd9a8ff |
1113434204415 has 64 divisors (see below), whose sum is σ = 1966011530112. Its totient is φ = 534596198400.
The previous prime is 1113434204381. The next prime is 1113434204489. The reversal of 1113434204415 is 5144024343111.
It is not a de Polignac number, because 1113434204415 - 213 = 1113434196223 is a prime.
It is a super-2 number, since 2×11134342044152 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 24449947 + ... + 24495443.
It is an arithmetic number, because the mean of its divisors is an integer number (30718930158).
Almost surely, 21113434204415 is an apocalyptic number.
1113434204415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1113434204415 is a deficient number, since it is larger than the sum of its proper divisors (852577325697).
1113434204415 is a wasteful number, since it uses less digits than its factorization.
1113434204415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48620.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 1113434204415 its reverse (5144024343111), we get a palindrome (6257458547526).
The spelling of 1113434204415 in words is "one trillion, one hundred thirteen billion, four hundred thirty-four million, two hundred four thousand, four hundred fifteen".
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