1113440471641 has 2 divisors, whose sum is σ = 1113440471642. Its totient is φ = 1113440471640.

The previous prime is 1113440471621. The next prime is 1113440471699. The reversal of 1113440471641 is 1461740443111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 656903766016 + 456536705625 = 810496^2 + 675675^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113440471641 - 2¹³ = 1113440463449 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1113440471641.

It is not a weakly prime, because it can be changed into another prime (1113440471621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556720235820 + 556720235821.

It is an arithmetic number, because the mean of its divisors is an integer number (556720235821).

Almost surely, 2^{1113440471641} is an apocalyptic number.

It is an amenable number.

1113440471641 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113440471641 is an equidigital number, since it uses as much as digits as its factorization.

1113440471641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 37.

It can be divided in two parts, 1113440 and 471641, that added together give a square (1585081 = 1259²).

The spelling of 1113440471641 in words is "one trillion, one hundred thirteen billion, four hundred forty million, four hundred seventy-one thousand, six hundred forty-one".