1114013515001 has 2 divisors, whose sum is σ = 1114013515002. Its totient is φ = 1114013515000.

The previous prime is 1114013514961. The next prime is 1114013515019. The reversal of 1114013515001 is 1005153104111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1113132612601 + 880902400 = 1055051^2 + 29680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1114013515001 is a prime.

It is a super-2 number, since 2×1114013515001² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1114013515091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557006757500 + 557006757501.

It is an arithmetic number, because the mean of its divisors is an integer number (557006757501).

Almost surely, 2^{1114013515001} is an apocalyptic number.

It is an amenable number.

1114013515001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114013515001 is an equidigital number, since it uses as much as digits as its factorization.

1114013515001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 300, while the sum is 23.

Adding to 1114013515001 its reverse (1005153104111), we get a palindrome (2119166619112).

The spelling of 1114013515001 in words is "one trillion, one hundred fourteen billion, thirteen million, five hundred fifteen thousand, one".