1114013515003 has 4 divisors (see below), whose sum is σ = 1114024642920. Its totient is φ = 1114002387088.

The previous prime is 1114013515001. The next prime is 1114013515019. The reversal of 1114013515003 is 3005153104111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1114013515003 - 2¹ = 1114013515001 is a prime.

It is a super-2 number, since 2×1114013515003² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1114013515001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5412418 + ... + 5614471.

It is an arithmetic number, because the mean of its divisors is an integer number (278506160730).

Almost surely, 2^{1114013515003} is an apocalyptic number.

1114013515003 is a deficient number, since it is larger than the sum of its proper divisors (11127917).

1114013515003 is a wasteful number, since it uses less digits than its factorization.

1114013515003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11127916.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 1114013515003 its reverse (3005153104111), we get a palindrome (4119166619114).

The spelling of 1114013515003 in words is "one trillion, one hundred fourteen billion, thirteen million, five hundred fifteen thousand, three".