1114031313533 has 4 divisors (see below), whose sum is σ = 1114142293920. Its totient is φ = 1113920333148.

The previous prime is 1114031313523. The next prime is 1114031313617. The reversal of 1114031313533 is 3353131304111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1114031313533 - 2¹⁶ = 1114031247997 is a prime.

It is a super-2 number, since 2×1114031313533² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1114031313496 and 1114031313505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1114031313523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55475135 + ... + 55495212.

It is an arithmetic number, because the mean of its divisors is an integer number (278535573480).

Almost surely, 2^{1114031313533} is an apocalyptic number.

It is an amenable number.

1114031313533 is a deficient number, since it is larger than the sum of its proper divisors (110980387).

1114031313533 is a wasteful number, since it uses less digits than its factorization.

1114031313533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110980386.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 1114031313533 its reverse (3353131304111), we get a palindrome (4467162617644).

The spelling of 1114031313533 in words is "one trillion, one hundred fourteen billion, thirty-one million, three hundred thirteen thousand, five hundred thirty-three".