1114031364137 has 2 divisors, whose sum is σ = 1114031364138. Its totient is φ = 1114031364136.

The previous prime is 1114031364133. The next prime is 1114031364151. The reversal of 1114031364137 is 7314631304111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 809587852441 + 304443511696 = 899771^2 + 551764^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114031364137 - 2² = 1114031364133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1114031364097 and 1114031364106.

It is not a weakly prime, because it can be changed into another prime (1114031364133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557015682068 + 557015682069.

It is an arithmetic number, because the mean of its divisors is an integer number (557015682069).

Almost surely, 2^{1114031364137} is an apocalyptic number.

It is an amenable number.

1114031364137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114031364137 is an equidigital number, since it uses as much as digits as its factorization.

1114031364137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 1114031364137 its reverse (7314631304111), we get a palindrome (8428662668248).

The spelling of 1114031364137 in words is "one trillion, one hundred fourteen billion, thirty-one million, three hundred sixty-four thousand, one hundred thirty-seven".