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11141000421 = 33713666807
BaseRepresentation
bin10100110000000111…
…00010110011100101
31001202102202110110020
422120003202303211
5140304044003141
65041302145353
7543040640535
oct123003426345
931672673406
1011141000421
1147a7893571
1221ab122259
1310871c5155
147798d54c5
15453142266
hex2980e2ce5

11141000421 has 4 divisors (see below), whose sum is σ = 14854667232. Its totient is φ = 7427333612.

The previous prime is 11141000413. The next prime is 11141000483. The reversal of 11141000421 is 12400014111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11141000421 - 23 = 11141000413 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11141000421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11141000491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1856833401 + ... + 1856833406.

It is an arithmetic number, because the mean of its divisors is an integer number (3713666808).

Almost surely, 211141000421 is an apocalyptic number.

It is an amenable number.

11141000421 is a deficient number, since it is larger than the sum of its proper divisors (3713666811).

11141000421 is an equidigital number, since it uses as much as digits as its factorization.

11141000421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3713666810.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 11141000421 its reverse (12400014111), we get a palindrome (23541014532).

The spelling of 11141000421 in words is "eleven billion, one hundred forty-one million, four hundred twenty-one", and thus it is an aban number.

Divisors: 1 3 3713666807 11141000421